-y^2+4y^2=-9y^2

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Solution for -y^2+4y^2=-9y^2 equation: 



-y^2+4y^2=-9y^2

We move all terms to the left:

-y^2+4y^2-(-9y^2)=0

We add all the numbers together, and all the variables

3y^2-(-9y^2)=0

We get rid of parentheses

3y^2+9y^2=0

We add all the numbers together, and all the variables

12y^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{24}=0$

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